Question: A compound was analyzed and was found to contain the following percentages of the elements by mass: boron, 78.14%; hydrogen, 21.86%. Determine the empirical formula of the compound.?

A compound was analyzed and was found to contain the following percentages of the elements by mass: boron, 78.14%; hydrogen, 21.86%. Determine the empirical formula of the compound.

 

Answer:

The empirical formula of a compound represents the simplest whole-number ratio of its constituent elements. To find the empirical formula, we first need to convert the percent composition by mass to moles. Then, divide each mole value by the smallest mole value to find the mole ratios. Finally, use these mole ratios to write the empirical formula.

 

Convert percent composition to moles:

Boron: 78.14 g/100 g * 1 mol/10.81 g = 7.22 moles

Hydrogen: 21.86 g/100 g * 1 mol/1.01 g = 21.70 moles

 

Find the mole ratios:

Boron: 7.22 moles / 7.22 moles = 1

Hydrogen: 21.70 moles / 7.22 moles = 3

 

Write the empirical formula:

Boron: 1 B

Hydrogen: 3 H

 

The empirical formula of the compound is BH3.

 

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